3.3.14 \(\int (e \cos (c+d x))^{7/2} (a+a \sin (c+d x))^3 \, dx\) [214]

3.3.14.1 Optimal result
3.3.14.2 Mathematica [C] (verified)
3.3.14.3 Rubi [A] (verified)
3.3.14.4 Maple [A] (verified)
3.3.14.5 Fricas [C] (verification not implemented)
3.3.14.6 Sympy [F(-1)]
3.3.14.7 Maxima [F]
3.3.14.8 Giac [F]
3.3.14.9 Mupad [F(-1)]

3.3.14.1 Optimal result

Integrand size = 25, antiderivative size = 203 \[ \int (e \cos (c+d x))^{7/2} (a+a \sin (c+d x))^3 \, dx=-\frac {34 a^3 (e \cos (c+d x))^{9/2}}{99 d e}+\frac {170 a^3 e^4 \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right )}{231 d \sqrt {e \cos (c+d x)}}+\frac {170 a^3 e^3 \sqrt {e \cos (c+d x)} \sin (c+d x)}{231 d}+\frac {34 a^3 e (e \cos (c+d x))^{5/2} \sin (c+d x)}{77 d}-\frac {2 a (e \cos (c+d x))^{9/2} (a+a \sin (c+d x))^2}{13 d e}-\frac {34 (e \cos (c+d x))^{9/2} \left (a^3+a^3 \sin (c+d x)\right )}{143 d e} \]

output
-34/99*a^3*(e*cos(d*x+c))^(9/2)/d/e+34/77*a^3*e*(e*cos(d*x+c))^(5/2)*sin(d 
*x+c)/d-2/13*a*(e*cos(d*x+c))^(9/2)*(a+a*sin(d*x+c))^2/d/e-34/143*(e*cos(d 
*x+c))^(9/2)*(a^3+a^3*sin(d*x+c))/d/e+170/231*a^3*e^4*(cos(1/2*d*x+1/2*c)^ 
2)^(1/2)/cos(1/2*d*x+1/2*c)*EllipticF(sin(1/2*d*x+1/2*c),2^(1/2))*cos(d*x+ 
c)^(1/2)/d/(e*cos(d*x+c))^(1/2)+170/231*a^3*e^3*sin(d*x+c)*(e*cos(d*x+c))^ 
(1/2)/d
 
3.3.14.2 Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.

Time = 0.04 (sec) , antiderivative size = 66, normalized size of antiderivative = 0.33 \[ \int (e \cos (c+d x))^{7/2} (a+a \sin (c+d x))^3 \, dx=-\frac {64 \sqrt [4]{2} a^3 (e \cos (c+d x))^{9/2} \operatorname {Hypergeometric2F1}\left (-\frac {17}{4},\frac {9}{4},\frac {13}{4},\frac {1}{2} (1-\sin (c+d x))\right )}{9 d e (1+\sin (c+d x))^{9/4}} \]

input
Integrate[(e*Cos[c + d*x])^(7/2)*(a + a*Sin[c + d*x])^3,x]
 
output
(-64*2^(1/4)*a^3*(e*Cos[c + d*x])^(9/2)*Hypergeometric2F1[-17/4, 9/4, 13/4 
, (1 - Sin[c + d*x])/2])/(9*d*e*(1 + Sin[c + d*x])^(9/4))
 
3.3.14.3 Rubi [A] (verified)

Time = 0.91 (sec) , antiderivative size = 213, normalized size of antiderivative = 1.05, number of steps used = 14, number of rules used = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.560, Rules used = {3042, 3157, 3042, 3157, 3042, 3148, 3042, 3115, 3042, 3115, 3042, 3121, 3042, 3120}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int (a \sin (c+d x)+a)^3 (e \cos (c+d x))^{7/2} \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int (a \sin (c+d x)+a)^3 (e \cos (c+d x))^{7/2}dx\)

\(\Big \downarrow \) 3157

\(\displaystyle \frac {17}{13} a \int (e \cos (c+d x))^{7/2} (\sin (c+d x) a+a)^2dx-\frac {2 a (a \sin (c+d x)+a)^2 (e \cos (c+d x))^{9/2}}{13 d e}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {17}{13} a \int (e \cos (c+d x))^{7/2} (\sin (c+d x) a+a)^2dx-\frac {2 a (a \sin (c+d x)+a)^2 (e \cos (c+d x))^{9/2}}{13 d e}\)

\(\Big \downarrow \) 3157

\(\displaystyle \frac {17}{13} a \left (\frac {13}{11} a \int (e \cos (c+d x))^{7/2} (\sin (c+d x) a+a)dx-\frac {2 \left (a^2 \sin (c+d x)+a^2\right ) (e \cos (c+d x))^{9/2}}{11 d e}\right )-\frac {2 a (a \sin (c+d x)+a)^2 (e \cos (c+d x))^{9/2}}{13 d e}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {17}{13} a \left (\frac {13}{11} a \int (e \cos (c+d x))^{7/2} (\sin (c+d x) a+a)dx-\frac {2 \left (a^2 \sin (c+d x)+a^2\right ) (e \cos (c+d x))^{9/2}}{11 d e}\right )-\frac {2 a (a \sin (c+d x)+a)^2 (e \cos (c+d x))^{9/2}}{13 d e}\)

\(\Big \downarrow \) 3148

\(\displaystyle \frac {17}{13} a \left (\frac {13}{11} a \left (a \int (e \cos (c+d x))^{7/2}dx-\frac {2 a (e \cos (c+d x))^{9/2}}{9 d e}\right )-\frac {2 \left (a^2 \sin (c+d x)+a^2\right ) (e \cos (c+d x))^{9/2}}{11 d e}\right )-\frac {2 a (a \sin (c+d x)+a)^2 (e \cos (c+d x))^{9/2}}{13 d e}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {17}{13} a \left (\frac {13}{11} a \left (a \int \left (e \sin \left (c+d x+\frac {\pi }{2}\right )\right )^{7/2}dx-\frac {2 a (e \cos (c+d x))^{9/2}}{9 d e}\right )-\frac {2 \left (a^2 \sin (c+d x)+a^2\right ) (e \cos (c+d x))^{9/2}}{11 d e}\right )-\frac {2 a (a \sin (c+d x)+a)^2 (e \cos (c+d x))^{9/2}}{13 d e}\)

\(\Big \downarrow \) 3115

\(\displaystyle \frac {17}{13} a \left (\frac {13}{11} a \left (a \left (\frac {5}{7} e^2 \int (e \cos (c+d x))^{3/2}dx+\frac {2 e \sin (c+d x) (e \cos (c+d x))^{5/2}}{7 d}\right )-\frac {2 a (e \cos (c+d x))^{9/2}}{9 d e}\right )-\frac {2 \left (a^2 \sin (c+d x)+a^2\right ) (e \cos (c+d x))^{9/2}}{11 d e}\right )-\frac {2 a (a \sin (c+d x)+a)^2 (e \cos (c+d x))^{9/2}}{13 d e}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {17}{13} a \left (\frac {13}{11} a \left (a \left (\frac {5}{7} e^2 \int \left (e \sin \left (c+d x+\frac {\pi }{2}\right )\right )^{3/2}dx+\frac {2 e \sin (c+d x) (e \cos (c+d x))^{5/2}}{7 d}\right )-\frac {2 a (e \cos (c+d x))^{9/2}}{9 d e}\right )-\frac {2 \left (a^2 \sin (c+d x)+a^2\right ) (e \cos (c+d x))^{9/2}}{11 d e}\right )-\frac {2 a (a \sin (c+d x)+a)^2 (e \cos (c+d x))^{9/2}}{13 d e}\)

\(\Big \downarrow \) 3115

\(\displaystyle \frac {17}{13} a \left (\frac {13}{11} a \left (a \left (\frac {5}{7} e^2 \left (\frac {1}{3} e^2 \int \frac {1}{\sqrt {e \cos (c+d x)}}dx+\frac {2 e \sin (c+d x) \sqrt {e \cos (c+d x)}}{3 d}\right )+\frac {2 e \sin (c+d x) (e \cos (c+d x))^{5/2}}{7 d}\right )-\frac {2 a (e \cos (c+d x))^{9/2}}{9 d e}\right )-\frac {2 \left (a^2 \sin (c+d x)+a^2\right ) (e \cos (c+d x))^{9/2}}{11 d e}\right )-\frac {2 a (a \sin (c+d x)+a)^2 (e \cos (c+d x))^{9/2}}{13 d e}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {17}{13} a \left (\frac {13}{11} a \left (a \left (\frac {5}{7} e^2 \left (\frac {1}{3} e^2 \int \frac {1}{\sqrt {e \sin \left (c+d x+\frac {\pi }{2}\right )}}dx+\frac {2 e \sin (c+d x) \sqrt {e \cos (c+d x)}}{3 d}\right )+\frac {2 e \sin (c+d x) (e \cos (c+d x))^{5/2}}{7 d}\right )-\frac {2 a (e \cos (c+d x))^{9/2}}{9 d e}\right )-\frac {2 \left (a^2 \sin (c+d x)+a^2\right ) (e \cos (c+d x))^{9/2}}{11 d e}\right )-\frac {2 a (a \sin (c+d x)+a)^2 (e \cos (c+d x))^{9/2}}{13 d e}\)

\(\Big \downarrow \) 3121

\(\displaystyle \frac {17}{13} a \left (\frac {13}{11} a \left (a \left (\frac {5}{7} e^2 \left (\frac {e^2 \sqrt {\cos (c+d x)} \int \frac {1}{\sqrt {\cos (c+d x)}}dx}{3 \sqrt {e \cos (c+d x)}}+\frac {2 e \sin (c+d x) \sqrt {e \cos (c+d x)}}{3 d}\right )+\frac {2 e \sin (c+d x) (e \cos (c+d x))^{5/2}}{7 d}\right )-\frac {2 a (e \cos (c+d x))^{9/2}}{9 d e}\right )-\frac {2 \left (a^2 \sin (c+d x)+a^2\right ) (e \cos (c+d x))^{9/2}}{11 d e}\right )-\frac {2 a (a \sin (c+d x)+a)^2 (e \cos (c+d x))^{9/2}}{13 d e}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {17}{13} a \left (\frac {13}{11} a \left (a \left (\frac {5}{7} e^2 \left (\frac {e^2 \sqrt {\cos (c+d x)} \int \frac {1}{\sqrt {\sin \left (c+d x+\frac {\pi }{2}\right )}}dx}{3 \sqrt {e \cos (c+d x)}}+\frac {2 e \sin (c+d x) \sqrt {e \cos (c+d x)}}{3 d}\right )+\frac {2 e \sin (c+d x) (e \cos (c+d x))^{5/2}}{7 d}\right )-\frac {2 a (e \cos (c+d x))^{9/2}}{9 d e}\right )-\frac {2 \left (a^2 \sin (c+d x)+a^2\right ) (e \cos (c+d x))^{9/2}}{11 d e}\right )-\frac {2 a (a \sin (c+d x)+a)^2 (e \cos (c+d x))^{9/2}}{13 d e}\)

\(\Big \downarrow \) 3120

\(\displaystyle \frac {17}{13} a \left (\frac {13}{11} a \left (a \left (\frac {5}{7} e^2 \left (\frac {2 e^2 \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right )}{3 d \sqrt {e \cos (c+d x)}}+\frac {2 e \sin (c+d x) \sqrt {e \cos (c+d x)}}{3 d}\right )+\frac {2 e \sin (c+d x) (e \cos (c+d x))^{5/2}}{7 d}\right )-\frac {2 a (e \cos (c+d x))^{9/2}}{9 d e}\right )-\frac {2 \left (a^2 \sin (c+d x)+a^2\right ) (e \cos (c+d x))^{9/2}}{11 d e}\right )-\frac {2 a (a \sin (c+d x)+a)^2 (e \cos (c+d x))^{9/2}}{13 d e}\)

input
Int[(e*Cos[c + d*x])^(7/2)*(a + a*Sin[c + d*x])^3,x]
 
output
(-2*a*(e*Cos[c + d*x])^(9/2)*(a + a*Sin[c + d*x])^2)/(13*d*e) + (17*a*((-2 
*(e*Cos[c + d*x])^(9/2)*(a^2 + a^2*Sin[c + d*x]))/(11*d*e) + (13*a*((-2*a* 
(e*Cos[c + d*x])^(9/2))/(9*d*e) + a*((2*e*(e*Cos[c + d*x])^(5/2)*Sin[c + d 
*x])/(7*d) + (5*e^2*((2*e^2*Sqrt[Cos[c + d*x]]*EllipticF[(c + d*x)/2, 2])/ 
(3*d*Sqrt[e*Cos[c + d*x]]) + (2*e*Sqrt[e*Cos[c + d*x]]*Sin[c + d*x])/(3*d) 
))/7)))/11))/13
 

3.3.14.3.1 Defintions of rubi rules used

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3115
Int[((b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(-b)*Cos[c + d* 
x]*((b*Sin[c + d*x])^(n - 1)/(d*n)), x] + Simp[b^2*((n - 1)/n)   Int[(b*Sin 
[c + d*x])^(n - 2), x], x] /; FreeQ[{b, c, d}, x] && GtQ[n, 1] && IntegerQ[ 
2*n]
 

rule 3120
Int[1/Sqrt[sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2/d)*EllipticF[(1/2 
)*(c - Pi/2 + d*x), 2], x] /; FreeQ[{c, d}, x]
 

rule 3121
Int[((b_)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(b*Sin[c + d*x]) 
^n/Sin[c + d*x]^n   Int[Sin[c + d*x]^n, x], x] /; FreeQ[{b, c, d}, x] && Lt 
Q[-1, n, 1] && IntegerQ[2*n]
 

rule 3148
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x 
_)]), x_Symbol] :> Simp[(-b)*((g*Cos[e + f*x])^(p + 1)/(f*g*(p + 1))), x] + 
 Simp[a   Int[(g*Cos[e + f*x])^p, x], x] /; FreeQ[{a, b, e, f, g, p}, x] && 
 (IntegerQ[2*p] || NeQ[a^2 - b^2, 0])
 

rule 3157
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x 
_)])^(m_), x_Symbol] :> Simp[(-b)*(g*Cos[e + f*x])^(p + 1)*((a + b*Sin[e + 
f*x])^(m - 1)/(f*g*(m + p))), x] + Simp[a*((2*m + p - 1)/(m + p))   Int[(g* 
Cos[e + f*x])^p*(a + b*Sin[e + f*x])^(m - 1), x], x] /; FreeQ[{a, b, e, f, 
g, m, p}, x] && EqQ[a^2 - b^2, 0] && GtQ[m, 0] && NeQ[m + p, 0] && Integers 
Q[2*m, 2*p]
 
3.3.14.4 Maple [A] (verified)

Time = 47.62 (sec) , antiderivative size = 321, normalized size of antiderivative = 1.58

method result size
default \(\frac {2 a^{3} e^{4} \left (-88704 \left (\sin ^{15}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+157248 \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (\sin ^{12}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+310464 \left (\sin ^{13}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-393120 \left (\sin ^{10}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \cos \left (\frac {d x}{2}+\frac {c}{2}\right )-337568 \left (\sin ^{11}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+361296 \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (\sin ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+67760 \left (\sin ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-148824 \left (\sin ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \cos \left (\frac {d x}{2}+\frac {c}{2}\right )+126280 \left (\sin ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+12012 \left (\sin ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \cos \left (\frac {d x}{2}+\frac {c}{2}\right )-101948 \left (\sin ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+5694 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \cos \left (\frac {d x}{2}+\frac {c}{2}\right )-3315 \sqrt {\frac {1}{2}-\frac {\cos \left (d x +c \right )}{2}}\, \sqrt {2 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1}\, F\left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right ), \sqrt {2}\right )+30338 \left (\sin ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-3311 \sin \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{9009 \sin \left (\frac {d x}{2}+\frac {c}{2}\right ) \sqrt {-2 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) e +e}\, d}\) \(321\)
parts \(-\frac {2 a^{3} \sqrt {e \left (2 \left (\cos ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1\right ) \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}\, e^{4} \left (48 \left (\cos ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-120 \left (\cos ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+128 \left (\cos ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-72 \left (\cos ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+5 \sqrt {\frac {1}{2}-\frac {\cos \left (d x +c \right )}{2}}\, \sqrt {-2 \left (\cos ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+1}\, F\left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right ), \sqrt {2}\right )+16 \cos \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{21 \sqrt {-e \left (2 \left (\sin ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-\left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )\right )}\, \sin \left (\frac {d x}{2}+\frac {c}{2}\right ) \sqrt {e \left (2 \left (\cos ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1\right )}\, d}+\frac {2 a^{3} \left (\frac {\left (e \cos \left (d x +c \right )\right )^{\frac {13}{2}}}{13}-\frac {e^{2} \left (e \cos \left (d x +c \right )\right )^{\frac {9}{2}}}{9}\right )}{d \,e^{3}}-\frac {2 a^{3} \left (e \cos \left (d x +c \right )\right )^{\frac {9}{2}}}{3 d e}+\frac {4 a^{3} \sqrt {e \left (2 \left (\cos ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1\right ) \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}\, e^{4} \left (672 \left (\cos ^{13}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-2352 \left (\cos ^{11}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+3312 \left (\cos ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-2400 \left (\cos ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+922 \left (\cos ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-159 \left (\cos ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-5 \sqrt {\frac {1}{2}-\frac {\cos \left (d x +c \right )}{2}}\, \sqrt {-2 \left (\cos ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+1}\, F\left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right ), \sqrt {2}\right )+5 \cos \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{77 \sqrt {-e \left (2 \left (\sin ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-\left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )\right )}\, \sin \left (\frac {d x}{2}+\frac {c}{2}\right ) \sqrt {e \left (2 \left (\cos ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1\right )}\, d}\) \(512\)

input
int((e*cos(d*x+c))^(7/2)*(a+a*sin(d*x+c))^3,x,method=_RETURNVERBOSE)
 
output
2/9009/sin(1/2*d*x+1/2*c)/(-2*sin(1/2*d*x+1/2*c)^2*e+e)^(1/2)*a^3*e^4*(-88 
704*sin(1/2*d*x+1/2*c)^15+157248*cos(1/2*d*x+1/2*c)*sin(1/2*d*x+1/2*c)^12+ 
310464*sin(1/2*d*x+1/2*c)^13-393120*sin(1/2*d*x+1/2*c)^10*cos(1/2*d*x+1/2* 
c)-337568*sin(1/2*d*x+1/2*c)^11+361296*cos(1/2*d*x+1/2*c)*sin(1/2*d*x+1/2* 
c)^8+67760*sin(1/2*d*x+1/2*c)^9-148824*sin(1/2*d*x+1/2*c)^6*cos(1/2*d*x+1/ 
2*c)+126280*sin(1/2*d*x+1/2*c)^7+12012*sin(1/2*d*x+1/2*c)^4*cos(1/2*d*x+1/ 
2*c)-101948*sin(1/2*d*x+1/2*c)^5+5694*sin(1/2*d*x+1/2*c)^2*cos(1/2*d*x+1/2 
*c)-3315*(sin(1/2*d*x+1/2*c)^2)^(1/2)*(2*sin(1/2*d*x+1/2*c)^2-1)^(1/2)*Ell 
ipticF(cos(1/2*d*x+1/2*c),2^(1/2))+30338*sin(1/2*d*x+1/2*c)^3-3311*sin(1/2 
*d*x+1/2*c))/d
 
3.3.14.5 Fricas [C] (verification not implemented)

Result contains higher order function than in optimal. Order 9 vs. order 4.

Time = 0.13 (sec) , antiderivative size = 158, normalized size of antiderivative = 0.78 \[ \int (e \cos (c+d x))^{7/2} (a+a \sin (c+d x))^3 \, dx=\frac {-3315 i \, \sqrt {2} a^{3} e^{\frac {7}{2}} {\rm weierstrassPInverse}\left (-4, 0, \cos \left (d x + c\right ) + i \, \sin \left (d x + c\right )\right ) + 3315 i \, \sqrt {2} a^{3} e^{\frac {7}{2}} {\rm weierstrassPInverse}\left (-4, 0, \cos \left (d x + c\right ) - i \, \sin \left (d x + c\right )\right ) + 2 \, {\left (693 \, a^{3} e^{3} \cos \left (d x + c\right )^{6} - 4004 \, a^{3} e^{3} \cos \left (d x + c\right )^{4} - 39 \, {\left (63 \, a^{3} e^{3} \cos \left (d x + c\right )^{4} - 51 \, a^{3} e^{3} \cos \left (d x + c\right )^{2} - 85 \, a^{3} e^{3}\right )} \sin \left (d x + c\right )\right )} \sqrt {e \cos \left (d x + c\right )}}{9009 \, d} \]

input
integrate((e*cos(d*x+c))^(7/2)*(a+a*sin(d*x+c))^3,x, algorithm="fricas")
 
output
1/9009*(-3315*I*sqrt(2)*a^3*e^(7/2)*weierstrassPInverse(-4, 0, cos(d*x + c 
) + I*sin(d*x + c)) + 3315*I*sqrt(2)*a^3*e^(7/2)*weierstrassPInverse(-4, 0 
, cos(d*x + c) - I*sin(d*x + c)) + 2*(693*a^3*e^3*cos(d*x + c)^6 - 4004*a^ 
3*e^3*cos(d*x + c)^4 - 39*(63*a^3*e^3*cos(d*x + c)^4 - 51*a^3*e^3*cos(d*x 
+ c)^2 - 85*a^3*e^3)*sin(d*x + c))*sqrt(e*cos(d*x + c)))/d
 
3.3.14.6 Sympy [F(-1)]

Timed out. \[ \int (e \cos (c+d x))^{7/2} (a+a \sin (c+d x))^3 \, dx=\text {Timed out} \]

input
integrate((e*cos(d*x+c))**(7/2)*(a+a*sin(d*x+c))**3,x)
 
output
Timed out
 
3.3.14.7 Maxima [F]

\[ \int (e \cos (c+d x))^{7/2} (a+a \sin (c+d x))^3 \, dx=\int { \left (e \cos \left (d x + c\right )\right )^{\frac {7}{2}} {\left (a \sin \left (d x + c\right ) + a\right )}^{3} \,d x } \]

input
integrate((e*cos(d*x+c))^(7/2)*(a+a*sin(d*x+c))^3,x, algorithm="maxima")
 
output
integrate((e*cos(d*x + c))^(7/2)*(a*sin(d*x + c) + a)^3, x)
 
3.3.14.8 Giac [F]

\[ \int (e \cos (c+d x))^{7/2} (a+a \sin (c+d x))^3 \, dx=\int { \left (e \cos \left (d x + c\right )\right )^{\frac {7}{2}} {\left (a \sin \left (d x + c\right ) + a\right )}^{3} \,d x } \]

input
integrate((e*cos(d*x+c))^(7/2)*(a+a*sin(d*x+c))^3,x, algorithm="giac")
 
output
integrate((e*cos(d*x + c))^(7/2)*(a*sin(d*x + c) + a)^3, x)
 
3.3.14.9 Mupad [F(-1)]

Timed out. \[ \int (e \cos (c+d x))^{7/2} (a+a \sin (c+d x))^3 \, dx=\int {\left (e\,\cos \left (c+d\,x\right )\right )}^{7/2}\,{\left (a+a\,\sin \left (c+d\,x\right )\right )}^3 \,d x \]

input
int((e*cos(c + d*x))^(7/2)*(a + a*sin(c + d*x))^3,x)
 
output
int((e*cos(c + d*x))^(7/2)*(a + a*sin(c + d*x))^3, x)